90 seconds of digit-counting
How many digits is the answer? Don't compute the product β just count the digits.
Suppose you see 823 × 612. Both numbers have 3 digits. The product has either 3+3-1 = 5 digits or 3+3 = 6 digits. Which one?
Look at just the leading digits: 8 × 6 = 48. Because that's 10 or more, we carry up to the bigger answer:
3 + 3 = 6 digits (true: 503,676 ✓)
For a d₁-digit number times a d₂-digit number:
A d-digit number lives in the range [10d−1, 10d). Multiplying a d₁-digit by a d₂-digit lands you in [10d₁+d₂−2, 10d₁+d₂), which is exactly two possible digit-counts. The leading-digit product tells you which side of the threshold you land on.
The real test isn't lead-digit × lead-digit — it's the full mantissa product. Each number is really lead.rest × 10d−1. If those mantissas multiply to ≥10, you carry up.
142 × 750 → lead product 1×7 = 7 says 5 digits. But mantissas 1.42 × 7.5 = 10.65 → carries up to 6 digits (true: 106,500). The shortcut lied.
Rule of thumb: when the lead-digit product is 6, 7, 8, or 9 and either number has a non-trivial second digit (3+), do a quick mantissa check before committing. Lead 1×7 with second digits 4 and 5? That's really 1.4 × 7.5 ≈ 10 — carry up.
Every question has a 30-second shot clock.
Bug, wording issue, or polish suggestion β all go straight into the dogfood backlog.